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On real numbers, (aRb) iff (a-b>1). Which statement is correct?

Answer and explanation

Correct answer: it is transitive but neither reflexive nor symmetric

Step 1: (a-a=0), which is not greater than (1), so it is not reflexive. Step 2: If (3R1) holds, (1R3) does not, so it is not symmetric. Step 3: If (a-b>1) and (b-c>1), then (a-c>2), so it is transitive.

Related tags

RelationsInequalityTransitiveExpertIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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