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On real numbers, (aRb) iff (|a-b|<1). What type of relation is it?

Answer and explanation

Correct answer: reflexive and symmetric but not transitive

Step 1: (|a-a|=0<1), so it is reflexive. Step 2: Distance is the same in both directions, so it is symmetric. Step 3: (0R0.6) and (0.6R1.2) hold, but (0R1.2) fails; hence it is not transitive.

Related tags

RelationsDistance-RelationReflexive-SymmetricExpertIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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