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On integers, (aRb) iff (2a+3b) is divisible by (5). In which property does this relation fail?

Answer and explanation

Correct answer: none

Step 1: (2a+3a=5a) is always divisible by (5), so the relation is reflexive. Step 2: (2a+3b\equiv0\pmod5) also gives (2b+3a\equiv0\pmod5). Step 3: The condition is equivalent to (a\equiv b\pmod5), so it is also transitive.

Related tags

RelationsModular-RelationEquivalenceExpertIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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