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On (A={1,2,3}), (R={(1,1),(2,2),(3,3),(1,2),(2,1)}) and (S={(1,1),(2,2),(3,3),(2,3),(3,2)}). Why is (R\cup S) not an equivalence relation?

Answer and explanation

Correct answer: ((1,3)) is missing, so transitivity fails

Step 1: The union contains all diagonal pairs and the needed reverse pairs. Step 2: It also contains ((1,2)) and ((2,3)). Step 3: Transitivity requires ((1,3)), which is missing, so it is not an equivalence relation.

Related tags

RelationsUnionEquivalence-CounterexampleExpertIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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