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On (A={1,2,3,4}), how many equivalence relations have exactly two equivalence classes?

Answer and explanation

Correct answer: (7)

Step 1: Exactly two classes means partitioning (4) elements into two non-empty disjoint parts. Step 2: There are (2^4-2=14) non-empty proper subsets, but each partition is counted twice. Step 3: Therefore the count is (\frac{14}{2}=7).

Related tags

RelationsEquivalence-ClassesPartitionCountingIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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