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On (A={1,2,3}), (R={(1,1),(2,2),(3,3),(1,2),(2,1),(1,3),(3,1)}). Why is it not an equivalence relation?

Answer and explanation

Correct answer: absence of ((2,3)) breaks transitivity

Step 1: All diagonal pairs are present, so reflexivity holds. Step 2: The reverses of ((1,2)) and ((1,3)) are also present, so symmetry holds. Step 3: From ((2,1)) and ((1,3)), ((2,3)) is required but missing; hence transitivity fails.

Related tags

RelationsEquivalenceTransitivity-FailOrdered-PairsIntroduction To RelationsRelations And FunctionsMathematicsClass 12 Mcq

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