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Class 12MathematicsRelations and FunctionsFunctionsExpert
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What is the real domain of (f(x)=\frac{1}{\sqrt{x-2}})?

Answer and explanation

Correct answer: ((2,\infty))

Step 1: For the square root, (x-2\geq0) is needed. Step 2: Since the square root is in the denominator, (x-2=0) is not allowed. Step 3: Combining both conditions gives (x>2).

Related tags

FunctionsDomainDenominatorSquare-RootRelations And FunctionsMathematicsClass 12 Mcq
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  3. 3In a function (f:A\to B), what is (A) called?
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  6. 6If (f={(1,2),(2,4),(3,6)}), what is the range of (f)?
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  10. 10If f(x) = 3x − 1, what is the value of f(2) + f(0)?
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