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What is the range of (f:\mathbb{R}\to\mathbb{R}), (f(x)=x^2-6x+10)?फलन (f:\mathbb{R}\to\mathbb{R}), (f(x)=x^2-6x+10) का परास क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([1,\infty))([1,\infty))
Step 1: Rewrite (x^2-6x+10) as ((x-3)^2+1). Step 2: Since ((x-3)^2\ge 0), the minimum value is (1). Step 3: Therefore the range is ([1,\infty)).चरण 1: (x^2-6x+10=(x-3)^2+1)। चरण 2: ((x-3)^2\ge 0), इसलिए न्यूनतम मान (1) है। चरण 3: अतः परास ([1,\infty)) होगा।
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