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If (f:[0,\infty)\to[0,\infty)), (f(x)=x^2), what is (f^{-1}(x))?यदि (f:[0,\infty)\to[0,\infty)), (f(x)=x^2), तो (f^{-1}(x)) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\sqrt{x})(\sqrt{x})
Step 1: The domain is ([0,\infty)), so (x) cannot be negative. Step 2: From (y=x^2), we get (x=\sqrt{y}). Step 3: (-\sqrt{y}) is not allowed because the domain has no negative numbers.चरण 1: प्रांत ([0,\infty)) है, इसलिए (x) ऋणात्मक नहीं हो सकता। चरण 2: (y=x^2) से (x=\sqrt{y}) मिलेगा। चरण 3: यहाँ (-\sqrt{y}) नहीं लिया जाएगा क्योंकि प्रांत में ऋणात्मक संख्या नहीं है।
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