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If (f:[0,\pi]\to[-1,1]) is given by (f(x)=\cos x), what is (f^{-1}(0))?यदि (f:[0,\pi]\to[-1,1]) को (f(x)=\cos x) से दिया गया है, तो (f^{-1}(0)) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{\pi}{2})(\frac{\pi}{2})
Step 1: On the domain ([0,\pi]), (\cos x) is one-one. Step 2: The solution of (\cos x=0) is (x=\frac{\pi}{2}). Step 3: On a restricted domain, the inverse value is unique.चरण 1: दिए गए प्रांत ([0,\pi]) में (\cos x) एकैकी है। चरण 2: (\cos x=0) का हल (x=\frac{\pi}{2}) है। चरण 3: सीमित प्रांत में प्रतिलोम मान एक ही होता है।
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