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If (f(x)=\sqrt{9-x^2}), what is the real domain?यदि (f(x)=\sqrt{9-x^2}), तो वास्तविक प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-3,3])([-3,3])
Step 1: The expression inside the square root must satisfy (9-x^2\geq 0). Step 2: This gives (x^2\leq 9), meaning (-3\leq x\leq 3). Step 3: When square roots and squares appear together, solve the inequality carefully.चरण 1: वर्गमूल के अंदर (9-x^2\geq 0) होना चाहिए। चरण 2: इससे (x^2\leq 9), अर्थात (-3\leq x\leq 3) मिलता है। चरण 3: वर्गमूल और वर्ग दोनों होने पर असमानता को सावधानी से हल करें।
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