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Class 12MathematicsRelations and FunctionsFunctionsHard
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If (f(x)=\frac{x-1}{x+1}), where (x\neq -1), what is the value of (x) for which (f(x)=2)?

Answer and explanation

Correct answer: (-3)

Step 1: Write (\frac{x-1}{x+1}=2). Step 2: Then (x-1=2x+2), so (x=-3). Step 3: For rational functions, also check that the denominator is not zero.

Related tags

Rational-FunctionFunction-ValueDomainFunctionsRelations And FunctionsMathematicsClass 12 Mcq
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