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If (f:R\to R), (f(x)=|x-4|+1), what is the range?यदि (f:R\to R), (f(x)=|x-4|+1), तो परास क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([1,\infty))([1,\infty))
Step 1: (|x-4|\ge0) for every real (x). Step 2: Therefore (|x-4|+1\ge1). Step 3: At (x=4), the minimum value (1) is obtained, so the range is ([1,\infty)).चरण 1: (|x-4|\ge0) हर वास्तविक (x) के लिए। चरण 2: इसलिए (|x-4|+1\ge1)। चरण 3: (x=4) पर न्यूनतम मान (1) मिलता है, अतः परास ([1,\infty)) है।
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