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If (f:[0,\infty)\to[1,\infty)), (f(x)=x^2+1), what is (f^{-1}(10))?यदि (f:[0,\infty)\to[1,\infty)), (f(x)=x^2+1), तो (f^{-1}(10)) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
Step 1: To find (f^{-1}(10)), solve (x^2+1=10). Step 2: (x^2=9), so (x=3) or (x=-3). Step 3: Since the domain is ([0,\infty)), only (3) is valid.चरण 1: (f^{-1}(10)) के लिए (x^2+1=10) हल करें। चरण 2: (x^2=9), इसलिए (x=3) या (x=-3)। चरण 3: प्रान्त ([0,\infty)) है, इसलिए केवल (3) मान्य है।
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