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Class 12MathematicsRelations and FunctionsFunctionsMedium
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If (f:R\to R), (f(x)=x^2+6x+10), what is the minimum value?

Answer and explanation

Correct answer: (1)

Step 1: Write (x^2+6x+10=(x+3)^2+1). Step 2: Since ((x+3)^2\ge0), (f(x)\ge1). Step 3: The minimum value is (1), attained at (x=-3).

Related tags

Minimum ValueQuadratic FunctionRangeMediumFunctionsRelations And FunctionsMathematicsClass 12 Mcq
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