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Class 12MathematicsRelations and FunctionsFunctionsMedium
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If (f:R\to R), (f(x)=x^2+4x+7), what is the range of (f)?

Answer and explanation

Correct answer: ([3,\infty))

Step 1: Write (x^2+4x+7=(x+2)^2+3). Step 2: Since ((x+2)^2\ge0), (f(x)\ge3). Step 3: The minimum value is (3), so the range is ([3,\infty)).

Related tags

RangeQuadratic FunctionComplete SquareMediumFunctionsRelations And FunctionsMathematicsClass 12 Mcq
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