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If (f(x)=\frac{x}{x+1}), does (f(x)=1) have a real solution?यदि (f(x)=\frac{x}{x+1}), तो (f(x)=1) का कोई वास्तविक हल है या नहीं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: No, it has no real solutionनहीं, कोई वास्तविक हल नहीं है
Step 1: Assume (\frac{x}{x+1}=1). Step 2: This gives (x=x+1), which is impossible. Step 3: Therefore (1) is not in the range of this function.चरण 1: (\frac{x}{x+1}=1) मानें। चरण 2: इससे (x=x+1) मिलता है, जो असंभव है। चरण 3: इसलिए (1) इस फलन के परास में नहीं आता।
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