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If (f(x)=\frac{x+3}{x^2-9}), what is the real domain?यदि (f(x)=\frac{x+3}{x^2-9}), तो वास्तविक प्रान्त क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (R-{-3,3})(R-{-3,3})
Step 1: The denominator is (x^2-9=(x-3)(x+3)). Step 2: The denominator must not be zero, so (x\ne3) and (x\ne-3). Step 3: Even if (x+3) cancels algebraically, (x=-3) is not allowed in the original function.चरण 1: हर (x^2-9=(x-3)(x+3)) है। चरण 2: हर शून्य न हो, इसलिए (x\ne3) और (x\ne-3)। चरण 3: ऊपर (x+3) कट सकता है, फिर भी मूल फलन में (x=-3) मान्य नहीं होगा।
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