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Class 12MathematicsRelations and FunctionsFunctionsMedium
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If (f(x)=\frac{1}{\sqrt{x-1}}), what is the real domain?

Answer and explanation

Correct answer: ((1,\infty))

Step 1: For the square root, (x-1\ge0) is needed. Step 2: But (\sqrt{x-1}) is in the denominator, so it cannot be zero. Step 3: Thus (x-1>0), so the domain is ((1,\infty)).

Related tags

DomainRadical DenominatorReal FunctionMediumFunctionsRelations And FunctionsMathematicsClass 12 Mcq
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