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If (f(x)=\sqrt{x-2}), what is the real domain?यदि (f(x)=\sqrt{x-2}), तो वास्तविक प्रान्त कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([2,\infty))([2,\infty))
Step 1: The expression inside the square root, (x-2), must be non-negative. Step 2: (x-2\ge0) gives (x\ge2). Step 3: At (x=2), the value is (0), so (2) is included.चरण 1: वर्गमूल के अंदर (x-2) ऋणात्मक नहीं होना चाहिए। चरण 2: (x-2\ge0) से (x\ge2) मिलता है। चरण 3: (x=2) पर मान (0) है, इसलिए (2) शामिल होगा।
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