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Class 12MathematicsRelations and FunctionsFunctionsEasy
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Why is (f:R\to R), (f(x)=9), not one-one?

Answer and explanation

Correct answer: Because (f(1)=f(2))

Step 1: In a one-one function, different inputs must have different images. Step 2: Here (1\ne2), but (f(1)=9) and (f(2)=9). Step 3: Therefore the constant function is not one-one.

Related tags

Constant FunctionNot One OneMany OneFunctionsRelations And FunctionsMathematicsClass 12 Mcq
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  1. 1If (f:A\to B) is a function, what condition is necessary for every element of (A)?
  2. 2If (f(x)=2x+3), what is the value of (f(4))?
  3. 3In a function (f:A\to B), what is (A) called?
  4. 4In a function (f:A\to B), what is (B) called?
  5. 5If (f={(1,2),(2,4),(3,6)}), what is the domain of (f)?
  6. 6If (f={(1,2),(2,4),(3,6)}), what is the range of (f)?
  7. 7Which of the following relations from (A={1,2}) to (B={3,4}) is a function?
  8. 8If (f(x)=x^2) and the domain is ({-2,-1,0,1,2}), what is the range?
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  10. 10If f(x) = 3x − 1, what is the value of f(2) + f(0)?
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