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What is the range of (f:R\to R), (f(x)=x^2+9)?फलन (f:R\to R), (f(x)=x^2+9) का परास क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([9,\infty))([9,\infty))
Step 1: For every real (x), (x^2\ge 0). Step 2: Therefore (x^2+9\ge 9). Step 3: The minimum value is (9), so the range is ([9,\infty)).चरण 1: हर वास्तविक (x) के लिए (x^2\ge 0)। चरण 2: इसलिए (x^2+9\ge 9)। चरण 3: न्यूनतम मान (9) है, अतः परास ([9,\infty)) है।
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