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If (f(x)=\sqrt{x+2}), what is the real domain?यदि (f(x)=\sqrt{x+2}), तो वास्तविक प्रान्त कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-2,\infty))([-2,\infty))
Step 1: The expression inside the square root, (x+2), must be non-negative. Step 2: (x+2\ge 0) gives (x\ge -2). Step 3: Hence the real domain is ([-2,\infty)).चरण 1: वर्गमूल के अंदर (x+2) ऋणात्मक नहीं होना चाहिए। चरण 2: (x+2\ge 0) से (x\ge -2) मिलता है। चरण 3: इसलिए वास्तविक प्रान्त ([-2,\infty)) है।
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