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If (f:R\to R), (f(x)=x^2+1), what is the range?यदि (f:R\to R), (f(x)=x^2+1), तो परास क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([1,\infty))([1,\infty))
Step 1: For every real (x), (x^2\ge 0). Step 2: Therefore (x^2+1\ge 1). Step 3: The minimum value is (1), so the range is ([1,\infty)).चरण 1: हर वास्तविक (x) के लिए (x^2\ge 0)। चरण 2: इसलिए (x^2+1\ge 1)। चरण 3: न्यूनतम मान (1) है, अतः परास ([1,\infty)) है।
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