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What is the real domain of (f(x)=\sqrt{x-1})?फलन (f(x)=\sqrt{x-1}) का वास्तविक प्रान्त कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([1,\infty))([1,\infty))
Step 1: The expression under the square root, (x-1), must be non-negative. Step 2: (x-1\ge 0) gives (x\ge 1). Step 3: Hence the real domain is ([1,\infty)).चरण 1: वर्गमूल के अंदर (x-1) ऋणात्मक नहीं होना चाहिए। चरण 2: (x-1\ge 0) से (x\ge 1) मिलता है। चरण 3: इसलिए वास्तविक प्रान्त ([1,\infty)) है।
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