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What is the real domain of (f(x)=\frac{1}{x-2})?फलन (f(x)=\frac{1}{x-2}) का वास्तविक प्रान्त क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (R-{2})(R-{2})
Step 1: The denominator (x-2) must not be zero. Step 2: (x-2=0) gives (x=2). Step 3: So all real numbers except (2) form the domain.चरण 1: हर (x-2) शून्य नहीं होना चाहिए। चरण 2: (x-2=0) से (x=2) मिलता है। चरण 3: इसलिए (2) को हटाकर बाकी सभी वास्तविक संख्याएँ प्रान्त हैं।
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