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On (A=\mathbb{R}\setminus{0}), (xRy) if (\frac{x}{y}>0). How many equivalence classes does this relation have?

Answer and explanation

Correct answer: Two

Step 1: (\frac{x}{y}>0) means (x) and (y) have the same sign. Step 2: All positive numbers form one class and all negative numbers form another. Step 3: For sign-based relations, split the set into positive and negative groups.

Related tags

Real NumbersSignEquivalence ClassesEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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