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If (A={1,2,3}), (R) has classes ({1,2},{3}), and (S) has classes ({1},{2,3}), why is (R\cup S) not an equivalence relation?

Answer and explanation

Correct answer: Because transitivity fails

Step 1: ((1,2)) belongs to (R\cup S) because it is in (R). Step 2: ((2,3)) belongs to (R\cup S) because it is in (S). Step 3: Transitivity would require ((1,3)), but it is in neither (R) nor (S).

Related tags

Union Of Equivalence RelationsTransitivity FailureFinite SetAdvancedEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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