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On positive integers, (aRb) if and only if (a) and (b) have the same last digit. What forms the equivalence class of (102)?

Answer and explanation

Correct answer: All positive integers with last digit (2)

Step 1: The last digit of (102) is (2). Step 2: The relation is based on equality of last digit. Step 3: So its class consists of all positive integers with last digit (2), not merely all even numbers.

Related tags

Last DigitEquivalence ClassPositive IntegersClassificationEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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