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On real numbers, (aRb) if and only if (a-b\in Q). Which is the equivalence class of (\sqrt{2})?

Answer and explanation

Correct answer: ({\sqrt{2}+q:q\in Q})

Step 1: A number (x) is related to (\sqrt{2}) when (x-\sqrt{2}) is rational. Step 2: So (x=\sqrt{2}+q), where (q\in Q). Step 3: Classes based on rational difference contain infinitely many numbers, not just one number.

Related tags

Rational DifferenceReal NumbersEquivalence ClassIrrational NumberEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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