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On non-zero integers, (aRb) if and only if (ab>0). How many equivalence classes are formed by this relation?

Answer and explanation

Correct answer: (2)

Step 1: (ab>0) means (a) and (b) are either both positive or both negative. Step 2: So all positive integers form one class and all negative integers form another. Step 3: Zero is not included in the set, so no separate zero class is formed.

Related tags

Nonzero IntegersSign RelationEquivalence ClassesProduct PositiveEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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