0 reads0 ratings0 helpful
If (R) is an equivalence relation and ([a]\subseteq [b]\cup[c]), with ([a]\cap[b]\neq\varnothing), which conclusion is correct?यदि (R) तुल्यता संबंध है और ([a]\subseteq [b]\cup[c]), तथा ([a]\cap[b]\neq\varnothing), तो कौन सा निष्कर्ष सही है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([a]=[b])([a]=[b])
Step 1: Since ([a]\cap[b]\neq\varnothing), the two equivalence classes are equal. Step 2: Hence ([a]=[b]) follows directly. Step 3: The union condition is extra; the key clue is the non-empty intersection.चरण 1: ([a]\cap[b]\neq\varnothing) होने से दो तुल्यता वर्ग समान होते हैं। चरण 2: इसलिए ([a]=[b]) तुरंत मिल जाता है। चरण 3: संघ वाली अतिरिक्त शर्त की जरूरत नहीं, मुख्य संकेत प्रतिच्छेद है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
