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On (A={1,2,3,4,5,6,7,8,9,10}), how many equivalence classes are formed by the relation (\tau(a)=\tau(b))?समुच्चय (A={1,2,3,4,5,6,7,8,9,10}) पर (\tau(a)=\tau(b)) से बने संबंध में कुल कितने तुल्यता वर्ग हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (4)(4)
Step 1: The divisor-count values appearing are (1,2,3,4). Step 2: The classes are ({1}), ({2,3,5,7}), ({4,9}), and ({6,8,10}). Step 3: The number of distinct (\tau)-values gives the number of classes.चरण 1: भाजक-संख्या के मान (1,2,3,4) मिलते हैं। चरण 2: वर्ग ({1}), ({2,3,5,7}), ({4,9}), ({6,8,10}) बनते हैं। चरण 3: अलग-अलग (\tau) मानों की संख्या ही वर्गों की संख्या है।
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