0 reads0 ratings0 helpful
On (A={1,2,3,4,5,6,7,8,9,10}), (aRb) holds when (\tau(a)=\tau(b)), where (\tau(n)) is the number of positive divisors. Which is the equivalence class of (6)?समुच्चय (A={1,2,3,4,5,6,7,8,9,10}) पर (aRb) तब है जब (\tau(a)=\tau(b)), जहाँ (\tau(n)) धनात्मक भाजकों की संख्या है। (6) का तुल्यता वर्ग कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ({6,8,10})({6,8,10})
Step 1: The divisors of (6) are (1,2,3,6), so (\tau(6)=4). Step 2: (8) and (10) also have (4) positive divisors. Step 3: Elements with the same divisor count form one equivalence class.चरण 1: (6) के भाजक (1,2,3,6) हैं, इसलिए (\tau(6)=4)। चरण 2: (8) और (10) के भी (4) धनात्मक भाजक हैं। चरण 3: समान भाजक-संख्या वाले तत्व एक ही तुल्यता वर्ग में आते हैं।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
