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On real numbers, (aRb) holds when (\cos a=\cos b). Which is the correct form of the equivalence class of (0)?

Answer and explanation

Correct answer: ({2n\pi:n\in\mathbb{Z}})

Step 1: (\cos 0=1). Step 2: The solutions of (\cos x=1) are (x=2n\pi), where (n\in\mathbb{Z}). Step 3: In trigonometric relations, include all angles with the same function value.

Related tags

Cosine FunctionEquivalence ClassReal NumbersEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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