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On (A={1,2,3,4,5,6}), (aRb) holds when (a\equiv b \pmod{2}). Which partition is formed by this relation?

Answer and explanation

Correct answer: ({1,3,5},{2,4,6})

Step 1: Having the same remainder modulo (2) means having the same parity. Step 2: Odd elements (1,3,5) and even elements (2,4,6) form two separate classes. Step 3: A modulo (2) relation splits a set into odd and even classes.

Related tags

Modulo 2PartitionParityEquivalence RelationRelations And FunctionsMathematicsClass 12 Mcq

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