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On (\mathbb{Z}), (a*b=a+b+ab). Which element is its own inverse?

Answer and explanation

Correct answer: (0)

Step 1: To be self-inverse, (a*a=0), since the identity is (0). Step 2: (a*a=2a+a^2=a(a+2)=0), so (a=0) or (a=-2). Step 3: Since both (0) and (-2) appear in the options, the item has two correct choices and must be corrected before use.

Related tags

Binary OperationsSelf InverseOption ValidationRelations And FunctionsMathematicsClass 12 Mcq

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