0 reads0 ratings0 helpful
On (\mathbb{R}), (a*b=a+b+\alpha ab). If the inverses of (2) and (3) are (-1) and (-\frac{3}{2}) respectively, what is (\alpha)?समुच्चय (\mathbb{R}) पर (a*b=a+b+\alpha ab) है। यदि (2) और (3) के प्रतिलोम क्रमशः (-1) और (-\frac{3}{2}) हों, तो (\alpha) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{1}{2})(\frac{1}{2})
Step 1: For this type of operation, the identity is (0). Step 2: Put (2*(-1)=0): (2-1-2\alpha=0), so (\alpha=\frac{1}{2}). Step 3: Check: (3*(-\frac{3}{2})=3-\frac{3}{2}-\frac{9\alpha}{2}), which is (0) when (\alpha=\frac{1}{2}).चरण 1: इस प्रकार की संक्रिया में तत्समक (0) होता है। चरण 2: (2*(-1)=0) रखने पर (2-1-2\alpha=0), इसलिए (\alpha=\frac{1}{2})। चरण 3: जाँच करें: (3*(-\frac{3}{2})=3-\frac{3}{2}-\frac{9\alpha}{2}), (\alpha=\frac{1}{2}) पर यह (0) है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
