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On positive real numbers, (a*b=a^{\log b}), where (\log) has base (10). When is this operation commutative?

Answer and explanation

Correct answer: For all (a,b>0)

Step 1: Commutativity needs (a*b=b*a). Step 2: Here (a^{\log b}=b^{\log a}). Taking (\log) on both sides gives ((\log a)(\log b)=(\log b)(\log a)), always true. Step 3: For exponential operations, logarithms often simplify comparison.

Related tags

Binary OperationsCommutativeLogarithmRelations And FunctionsMathematicsClass 12 Mcq

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