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On (\mathbb{N}), (a*b=\gcd(a,b)). Does the identity element lie in (\mathbb{N})?

Answer and explanation

Correct answer: No, because there is no largest natural element

Step 1: For (\gcd(a,e)=a), (e) must be a multiple of every (a). Step 2: There is no single natural number that is a multiple of all natural numbers. Step 3: If (0) were included, the situation would differ, but in (\mathbb{N}) there is no identity here.

Related tags

Binary OperationsGcdNo IdentityNatural NumbersRelations And FunctionsMathematicsClass 12 Mcq

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