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On natural numbers, (a*b=a+b-2). When does this operation fail to be closed on natural numbers?

Answer and explanation

Correct answer: When (a=1,b=1)

Step 1: Natural numbers are generally (1,2,3,\ldots). Step 2: (1*1=1+1-2=0), and (0) is not in this set. Hence closure fails. Step 3: For closure checks, always test the smallest elements.

Related tags

Binary OperationClosureNatural NumbersCounterexampleBinary OperationsRelations And FunctionsMathematicsClass 12 Mcq

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