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Which statement is correct for (0, 1) ⊆ [0, 1]?

Answer and explanation

Correct answer: It is true because every number in (0, 1) is in [0, 1].

The statement asks whether every element of the first interval belongs to the second interval. Any x in (0, 1) satisfies 0 < x < 1, which automatically implies 0 ≤ x ≤ 1. Hence x belongs to [0, 1], and the subset statement is true. The endpoints 0 and 1 need not belong to the first interval because they are not elements of it.

Related tags

Interval-SubsetOpen-Closed-IntervalInequalitiesSetsRepresentation On Number LineLinear InequalitiesMathematicsClass 12 Mcq

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