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What is the correct value of \(\tan\left(\cos^{-1}x\right)\), when \(0<x<1\)?\(\tan\left(\cos^{-1}x\right)\) का सही मान क्या है, जब \(0<x<1\)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\sqrt{1-x^2}}{x}\)\(\frac{\sqrt{1-x^2}}{x}\)
If \(\theta=\cos^{-1}x\), then \(\cos\theta=x\) and \(\sin\theta=\sqrt{1-x^2}\). Hence \(\tan\theta=\frac{\sqrt{1-x^2}}{x}\).यदि \(\theta=\cos^{-1}x\), तो \(\cos\theta=x\) और \(\sin\theta=\sqrt{1-x^2}\)। इसलिए \(\tan\theta=\frac{\sqrt{1-x^2}}{x}\)।
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