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What is the value of \(\cos\left(\tan^{-1}\frac{15}{8}\right)\)?\(\cos\left(\tan^{-1}\frac{15}{8}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{8}{17}\)\(\frac{8}{17}\)
If \(\tan\theta=\frac{15}{8}\), then the hypotenuse is (17). In the principal range \(\theta\) is in the first quadrant, so \(\cos\theta=\frac{8}{17}\).यदि \(\tan\theta=\frac{15}{8}\), तो कर्ण (17) है। मुख्य परिसर में \(\theta\) प्रथम चतुर्थांश में है, इसलिए \(\cos\theta=\frac{8}{17}\)।
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