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If \(\theta=\cos^{-1}\left(\frac{8}{17}\right)\), what is the value of \(\sin\theta\)?यदि \(\theta=\cos^{-1}\left(\frac{8}{17}\right)\), तो \(\sin\theta\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{15}{17}\)\(\frac{15}{17}\)
Here \(\theta\in\left[0,\pi\right]\) and \(\cos\theta=\frac{8}{17}\), so \(\theta\) is in the first quadrant and \(\sin\theta=\frac{15}{17}\). The triangle method is fast.\(\theta\in\left[0,\pi\right]\) और \(\cos\theta=\frac{8}{17}\), इसलिए \(\theta\) प्रथम चतुर्थांश में है और \(\sin\theta=\frac{15}{17}\)। त्रिभुज विधि तेज है।
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