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What is the value of \(tan^{-1}2+\tan^{-1}\left(\frac{1}{2}\right)\)?\(tan^{-1}2+\tan^{-1}\left(\frac{1}{2}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{2}\)\(\frac{\pi}{2}\)
Here \(2>0\), so \(tan^{-1}2+\tan^{-1}\left(\frac{1}{2}\right)=\frac{\pi}{2}\). Identify (x) and \(\frac{1}{x}\) in the identity.यहाँ \(2>0\), इसलिए \(tan^{-1}2+\tan^{-1}\left(\frac{1}{2}\right)=\frac{\pi}{2}\)। पहचान में (x) और \(\frac{1}{x}\) पहचानें।
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