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What is the value of \(tan^{-1}x+\tan^{-1}\left(\frac{1}{x}\right)\) when \(x>0\)?\(tan^{-1}x+\tan^{-1}\left(\frac{1}{x}\right)\) का मान क्या है जब \(x>0\)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{2}\)\(\frac{\pi}{2}\)
When \(x>0\), \(tan^{-1}x+\tan^{-1}\left(\frac{1}{x}\right)=\frac{\pi}{2}\). Always check the sign condition.जब \(x>0\), तब \(tan^{-1}x+\tan^{-1}\left(\frac{1}{x}\right)=\frac{\pi}{2}\)। चिन्ह की शर्त हमेशा देखें।
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