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What is the value of \(\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)+\sin^{-1}\left(\frac{1}{2}\right)\)?\(\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)+\sin^{-1}\left(\frac{1}{2}\right)\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{3}\)\(\frac{\pi}{3}\)
Here \(\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)=\frac{\pi}{6}\) and \(\sin^{-1}\left(\frac{1}{2}\right)=\frac{\pi}{6}\). Hence the sum is \(\frac{\pi}{3}\).\(\tan^{-1}\left(\frac{1}{\sqrt{3}}\right)=\frac{\pi}{6}\) और \(\sin^{-1}\left(\frac{1}{2}\right)=\frac{\pi}{6}\)। इसलिए योग \(\frac{\pi}{3}\) है।
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