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What is the principal value of \(\cos^{-1}\left(\cos\frac{4\pi}{3}\right)\)?\(\cos^{-1}\left(\cos\frac{4\pi}{3}\right)\) का मुख्य मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{2\pi}{3}\)\(\frac{2\pi}{3}\)
\(\cos\frac{4\pi}{3}=-\frac{1}{2}\), so \(\cos^{-1}\left(-\frac{1}{2}\right)=\frac{2\pi}{3}\). Give the answer of \(\cos^{-1}x) in ([0,\pi]\).\(\cos\frac{4\pi}{3}=-\frac{1}{2}\), इसलिए \(\cos^{-1}\left(-\frac{1}{2}\right)=\frac{2\pi}{3})। (\cos^{-1}x\) का उत्तर \([0,\pi]\) में दें।
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