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What is the principal value of \(\sin^{-1}\left(\frac{1}{2}\right)\)?\(\sin^{-1}\left(\frac{1}{2}\right)\) का मुख्य मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{\pi}{6}\)\(\frac{\pi}{6}\)
\(\sin\frac{\pi}{6}=\frac{1}{2}\) and \(\frac{\pi}{6}\) lies in the principal range. Always choose the value inside the principal range.\(\sin\frac{\pi}{6}=\frac{1}{2}\) और \(\frac{\pi}{6}\) मुख्य परिसर में है। मुख्य मान हमेशा range में चुनें।
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